DIY History | Transcribe | Scholarship at Iowa | Eccentricity of the Sextant by Frederic Furbish, 1893 | Eccentricity of the Sextant by Frederic Furbish, 1893, Page 118

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Eccentricity of the Sextant by Frederic Furbish, 1893

Eccentricity of the Sextant by Frederic Furbish, 1893, Page 118

[page][illegible][/page]

[items listed left to right by section?]

[aa]
[ab]
[ac]
[an]
[as]

log [aa]
log [ab]
log [ac]
log [an]
log [as]
-----------------------------------
[bb]
[bc]
[bn]
[bs]

log ([ab]/[aa])
[??log or no log??:]
((ab)/(aa))[ab]
((ab)/(aa))[ac]
((ab)/(aa))[an]
((ab)/(aa))[as]
-----------------------------------
[bb * 1]
[bc * 1]
[bn * 1]
[bs * 1]

Check sum.

log [bb * 1]
log [bc * 1]
log [bn * 1]
log [bs * 1]
-----------------------------------
[cc]
[cn]
[cs]

log ([ac]/[aa])
[??log or no log??:]
((ac)/(aa))[ac]
((ac)/(aa))[an]
((ac)/(aa))[as]
-----------------------------------
[cc * 1]
[cn * 1]
[cs * 1]

Check Sum.

log ([bc * 1]/[bb * 1])
((bc * 1)/(bb * 1))[bc * 1]
((bc * 1)/(bb * 1))[bn * 1]
((bc * 1)/(bb * 1))[bs * 1]
-----------------------------------
[cc * 2]
[cn * 2]
[cs * 2]

Check Sum.

log ([cn * 2]/[cc * 2])
log (cc * 2)
log (cn * 2)

The checks on the work are,-

(bs * 1) = (bb * 1) + (bc * 1) + (bn * 1)

(cs * 1) = (bc * 1) + (cc * 1) + (cn * 1)

(cs * 2) = (cc * 2) + (cn * 2) .

Applying this formula to [illegible?]our[/illegible?] normals we proceed as follows.

     Substituting the values of [aa], [ab] etc. in the first line we have.-

(See next page)

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[page][illegible][/page] [items listed left to right by section?] [aa] [ab] [ac] [an] [as] log [aa] log [ab] log [ac] log [an] log [as] ----------------------------------- [bb] [bc] [bn] [bs] log ([ab]/[aa]) [??log or no log??:] ((ab)/(aa))[ab] ((ab)/(aa))[ac] ((ab)/(aa))[an] ((ab)/(aa))[as] ----------------------------------- [bb * 1] [bc * 1] [bn * 1] [bs * 1] Check sum. log [bb * 1] log [bc * 1] log [bn * 1] log [bs * 1] ----------------------------------- [cc] [cn] [cs] log ([ac]/[aa]) [??log or no log??:] ((ac)/(aa))[ac] ((ac)/(aa))[an] ((ac)/(aa))[as] ----------------------------------- [cc * 1] [cn * 1] [cs * 1] Check Sum. log ([bc * 1]/[bb * 1]) ((bc * 1)/(bb * 1))[bc * 1] ((bc * 1)/(bb * 1))[bn * 1] ((bc * 1)/(bb * 1))[bs * 1] ----------------------------------- [cc * 2] [cn * 2] [cs * 2] Check Sum. log ([cn * 2]/[cc * 2]) log (cc * 2) log (cn * 2) The checks on the work are,- (bs * 1) = (bb * 1) + (bc * 1) + (bn * 1) (cs * 1) = (bc * 1) + (cc * 1) + (cn * 1) (cs * 2) = (cc * 2) + (cn * 2) . Applying this formula to [illegible?]our[/illegible?] normals we proceed as follows. Substituting the values of [aa], [ab] etc. in the first line we have.- (See next page)