DIY History | Transcribe | Scholarship at Iowa | Eccentricity of the Sextant by Frederic Furbish, 1893 | Eccentricity of the Sextant by Frederic Furbish, 1893, Page 129

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Eccentricity of the Sextant by Frederic Furbish, 1893

Eccentricity of the Sextant by Frederic Furbish, 1893, Page 129

Clock Correction      May 2, 1893
Stars, 101  K. Draconis.  R.A. 12h 23m 59.97s
          102  y Virginis.   12  36  15.83
          103  7  Cassiopiae.   12  50   12.50

Equations.-

(101) - 59.98 = ∆t - 1.43a + 2.98c

(102) - 42.02 = ∆t + 0.65a + 1.00c

(103) - 31.21 = ∆t + 1.97a - 2.01c.

(101) - 59.98 = [cancelled?]∆t[/cancelled?] - 1.43a + 2.98c

(102) - 42.02 = [cancelled?]∆t[/cancelled?] + 0.65a + 1.00c

          +          -                        -           -          
------------------------------------
(3) - 17.96 =      - 2.08a + 1.98c

(102) - 42.02 = [cancelled?]∆t[/cancelled?] + 0.65a + 1.00c

(103) - 31.21 = [cancelled?]∆t[/cancelled?] + 1.97a - 2.01c

          +                                   -           +          
------------------------------------
(4) - 10.81 =      - 1.32a + 3.01c

(3) + 23.7072 = + [cancelled?]( )[/cancelled?]a - 2.6136c
(4) + 22.4848 = + [cancelled?]( )[/cancelled?]a - 6.2608[?c?]

      -                     -                                                 +
------------------------------------
      +1.2224  =              3.6472c

    c = 0.3351s

Substituting in (4) a = 8.953s
          ∆t = - 48.1745s.

Saving...

Clock Correction May 2, 1893 Stars, 101 K. Draconis. R.A. 12h 23m 59.97s 102 y Virginis. 12 36 15.83 103 7 Cassiopiae. 12 50 12.50 Equations.- (101) - 59.98 = ∆t - 1.43a + 2.98c (102) - 42.02 = ∆t + 0.65a + 1.00c (103) - 31.21 = ∆t + 1.97a - 2.01c. (101) - 59.98 = [cancelled?]∆t[/cancelled?] - 1.43a + 2.98c (102) - 42.02 = [cancelled?]∆t[/cancelled?] + 0.65a + 1.00c + - - - ------------------------------------ (3) - 17.96 = - 2.08a + 1.98c (102) - 42.02 = [cancelled?]∆t[/cancelled?] + 0.65a + 1.00c (103) - 31.21 = [cancelled?]∆t[/cancelled?] + 1.97a - 2.01c + - + ------------------------------------ (4) - 10.81 = - 1.32a + 3.01c (3) + 23.7072 = + [cancelled?]( )[/cancelled?]a - 2.6136c (4) + 22.4848 = + [cancelled?]( )[/cancelled?]a - 6.2608[?c?] - - + ------------------------------------ +1.2224 = 3.6472c c = 0.3351s Substituting in (4) a = 8.953s ∆t = - 48.1745s.